RE: Times method

Trifon — Wed, 17 Mar 2004 19:44:06 GMT

When you use this statement:
[code]Dim M1, M2, M3, M4 As Matrix[/code]
variables M1,M2,M3 are declared as Variants and only variable M4 is
declared as a Matrix variable.
Try this:
[code]Dim M1, M2, M3, M4 As Matrix
Debug.Print TypeName(M1), TypeName(M4)[/code]
you will get : [code]Variant Matrix[/code]
In order to have this problem fixed please replace the Dim statement as follows:
[code]Dim M1 As Matrix, M2 As Matrix, M3 As Matrix, M4 As Matrix[/code]

Times method

anonymous — Wed, 17 Mar 2004 19:38:20 GMT

I've downloaded your software and am having problems with the times method.
I want to multiply a 3x3 matrix by a 3x1 matrix and get a type mismatch error. Your help file says that " The number or rows of Matrix2 parameter must be equal to number of columns of current Matrix" which I believe is the case.

The code I have used is:
[code] Dim M1, M2, M3, M4 As Matrix

Set M1 = New Matrix

M1.Rows = 3: M1.Cols = 3

M1.Item(0, 0) = 3
M1.Item(0, 1) = 4
M1.Item(0, 2) = 5
M1.Item(1, 0) = 6
M1.Item(1, 1) = 7
M1.Item(1, 2) = 8
M1.Item(2, 0) = 9
M1.Item(2, 1) = 10
M1.Item(2, 2) = 11

Set M2 = New Matrix
M2.Rows = 3: M2.Cols = 1

M2.Item(0, 0) = 1
M2.Item(1, 0) = 1
M2.Item(2, 0) = 1

Set M3 = M1.Times(M2) <---------- Type mismatch error here!
[/code]
Can you let me know why this doesn't work. More complicated functions such as inverse are working ok and multiplying 3x3 by 3x3 works.

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RE: Times method

Times method