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trace - sum of eigenvalues Expand / Collapse
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Posted Saturday, May 02, 2009 7:27 PM Post #545
 

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I submitted a matrix which I will give below. The trace was given as zero, the eigenvalues, when I added them up, summed to 1. I thought they should sum to zero (the trace). Can you explain what's happening?

Here is matrix I entered:

0 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
1 0 1 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0
1 1 0 1 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0
1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0
1 0 0 0 0 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 1 0 1 1 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 1 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0
0 1 0 0 0 0 0 0 0 1 1 1 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 1 0 1 1 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 1 1 0 1 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 1 1 1 0 0 0 0 0 0 0 0 0
0 0 1 0 0 0 0 0 0 0 0 0 0 1 1 1 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 1 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 1 1 0 1 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 0 0 0 0 0
0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 1
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 0 1
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 0

Posted Sunday, May 03, 2009 12:21 PM Post #546
 

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Hello,

I have checked the result and the eigenvalues sum to zero, which is the same as the trace. Please verify the result again.

Trifon Triantafillidis

Lead Developer

Bluebit Software

Posted Sunday, May 03, 2009 1:49 PM Post #547
 

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I did this again and the eigenvalues I get are:
igenvalues:

( 4, 0i)
( 3, 0i)
(-1, 0i)
( 0, 0i)
( 0, 0i)
( 3, 0i)
( 3, 0i)
( 3, 0i)
(-2, 0i)
(-2, 0i)
(-2, 0i)
( 0, 0i)
(-1, 0i)
(-1, 0i)
(-1, 0i)
(-1, 0i)
(-1, 0i)
(-1, 0i)
(-1, 0i)
(-1, 0i)

when I add this up it sums to one--there is positive four and three with multiplicity four, which gives sixteen; the negative eigenvalues are -2 (multiplicity three) and -1 (multiplicity 9) for a total of -15 -- and three times zero, which doesn't affect the sum. Please explain.
Posted Monday, May 04, 2009 11:02 AM Post #548
 

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That's funny, for the above matrix I get the following eigenvalues:

( 3.588, 0.000i)
( 2.594, 0.000i)
(-1.182, 0.000i)
(-0.172, 0.000i)
(-0.172, 0.000i)
( 3.064, 0.000i)
( 3.064, 0.000i)
( 3.064, 0.000i)
(-1.892, 0.000i)
(-1.892, 0.000i)
(-1.892, 0.000i)
(-0.172, 0.000i)
(-1.000, 0.000i)
(-1.000, 0.000i)
(-1.000, 0.000i)
(-1.000, 0.000i)
(-1.000, 0.000i)
(-1.000, 0.000i)
(-1.000, 0.000i)
(-1.000, 0.000i)

which they do sum to zero.

Trifon Triantafillidis

Lead Developer

Bluebit Software

Posted Monday, May 04, 2009 11:05 AM Post #549
 

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Oh, I think I got it!

It seems that you you setting "Show results using ... digits to" to 0 therefore the eigenvalues are rounded to the nearest whole number. Is that so?

Trifon Triantafillidis

Lead Developer

Bluebit Software

Posted Monday, May 04, 2009 2:46 PM Post #550
 

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yes -- had set digits to zero -- thanks for pointing it out. Thanks.
Posted Monday, June 06, 2011 6:51 AM Post #647
 

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Posted Monday, October 10, 2011 2:42 AM Post #735
 

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